Designing a power supply based on the integration of National LM317; applying an input voltage of about 28 V, output voltage, which is perfectly stable, can be adjusted from 2 to 25 V, simply by turning the potentiometer 5 kOhm.
As shown, the circuit is very simple and the pattern is descriptive, to allow the execution even the less experienced.
The AC voltage of the transformer is rectified by a diode bridge (you can also use 4 diodes).
The condenser (No. 2) from 2200 uF 50V measures at the level, while the small one (No. 1) from 0.01 uF in parallel, in the circumstances of peaks at high frequency, compensating for the inductance dell'elettrolitico. The condenser (No. 3) 100-uF 36V
The tension comes at pin 3 of integrity. Since the center pin out voltage regulated, while on pin 1 is connected to the network of regulation, made by the resistance of 240 W and 5 kW potentiometer.
(NB remember bridging two of the three terminals of the potentiometer).
The power supply can supply a maximum current of 1.5 A.
THE TRANSFORMER The transformer has the task to lower the voltage, it is generally composed of two distinct windings: one entry, called primary, which is connected to 220V, a output, called secondary, which provides a lower voltage of the incoming, suited to the needs of the user, that any equipment that you want food. Depending on the types, the processor may have one or two secondary windings;
rectifier diode
in electrical and electronic rectifier or a rectifier is a device used to straighten a bipolar signal ( bidirectional), and then to turn it into a unipolar signal (mono). The rectifier is connected to other components, is used to convert alternating current into direct current.
adopting four diodes arranged in a Graetz bridge configuration, You can get a signal which is the sum of a positive half wave over the negative half-wave inverted (full wave). This solution, widely used in power supplies, makes it much easier for the next filtering and voltage level to obtain a current, however, does not require a transformer with double windings. The main disadvantage of this method is to have a voltage drop equal to that of two diodes in series, and even beyond 2volt. In flattening very small voltages is therefore a loss and excessive distortion.
A similar configuration consists of six diodes can straighten a three-phase voltage using all three phases (more than three in a multiphase system, using a suitable number of diodes).
LEVELING THE CONDENSER
The AC voltage coming from the transformer, made by one-way diodes, does not have a constant value: the value is constantly changing, going from zero to a maximum value, and this happens as we said before, fifty times a second. The capacitor is added to the circuit works as a reserve tank: stores energy when the voltage is high and the returns when the voltage tends to drop.
Calculation for a power supply circuit to use depends on the transformer you have. When you need a stronger current is best to use the scheme with four diodes, which uses both half-waves and therefore allows a higher level of output voltage. With four diodes are both half-wave rectified.
to obtain the desired voltage output, the only way is to use a transformer whose secondary voltage gives a very precise. Let us see how it calculated the secondary voltage of the transformer:
VU
call the tension that has to come to the user.
add 1 to the value of VU to take into account the voltage drop in rectifiers
divide the result by 1.41 to go from maximum to rms
multiply the result by 1.1 to take account of the fall voltage in the transformer when operating under load
With these calculations we obtain that VS and the voltage that the transformer secondary must have, who does not want to do accounts in the table on the right is already calculated values.
Keep in mind that the values \u200b\u200bshown are approximate, partly because, unless you wrap it
specifically, hardly able to find a transformer with the correct voltage. The processor must then be adapted to the power demand: multiply the operating voltage for the power user who requires it, the value obtained shall be increased by about 20% if the power supply must operate intermittently, or 40% in
case of extended or continuous operation.
Example: an appliance has to operate at 12 V and consumes a current of 1.5 A and power of the transformer is:
the 12 x 1.5 x 1.2 = 21.6 VA (for intermittent operation)
l 12 x 1.5 x 1.4 = 25.2 VA (for continuous operation)